If the area of a circle is numerically equal to twice its circumference, then the diameter of the circle is :
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As per the given problem condition :
area of circle = 2(circumference)
πr^2 = 2(2πr)
πr^2 = 4 πr
πr×r = 4πr
r = 4πr/πr
r = 4
Diameter = 2r
= 2(4)
= 8
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