Question

If the area of a parallelogram is 240 sq. cm and base is 20 cm, then
find its height.

10 cm
24 cm
12 cm
14cm​

Answer 1

Given:

• Area of the parallelogram is 240 cm²
• Base of the parallelogram is 20 cm

⠀⠀⠀

Need to find: Height of the parallelogram.

⠀

$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$⠀⠀⠀⠀

⠀

$\star\;\boxed{\sf{\pink{Area_{\;(parallelogram)} = Base \times Height}}}$

⠀

Therefore,

⠀

$:\implies\sf 240 = 20 \times Height \\\\\\:\implies\sf Height = \cancel\dfrac{240}{20} \\\\\\:\implies{\underline{\boxed{\sf{\pink{Height = 12\;cm}}}}}\;\bigstar$

⠀

$\therefore{\underline{\sf{Hence,\; Height\;of\; the \: parallelogram\;is\; \bf{Option\;c)\; 12\;cm}.}}}$

⠀

⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀

⠀⠀⠀⠀⠀⠀

$\qquad\quad\boxed{\bf{\mid{\overline{\underline{\purple{\bigstar\: More \: to \; know \: :}}}}}\mid}$⠀

• A parallelogram is a shape in which sides are parallel to each other.

• Area of parallelogram, Area = Base × Height

• Perimeter of parallelogram, P = 2(a + b). Here, a and b are the length of sides of the parallelogram.

Answer 2

Question:-

• Area of Parallelogram is $\sf\green{240 cm^2}$

• Base of the Parallelogram is $\sf\pink{20 cm}$

To Find

• We have to find the Height of Parallelogram.

⠀

${\fcolorbox{blue}{black}{\purple{\:\:\:\:\:\:Area of Parallelogram is Base × Height \:\:\:\:\:\:}}}$

So, Now

⠀⠀⠀⠀$\sf\pink{⟹}$  240 = Base $\times$ Height

⠀⠀⠀⠀⠀⠀$\sf\blue{⟹}$ Height $\rightarrow$ ${{\cancel \frac{240}{20}}}$

⠀⠀⠀⠀${\fcolorbox{blue}{black}{\pink{\:\:\:\:\:Height ⟹ 12cm\:\:\:\:}}}$

•°• Hence, Verified that the answer will be option $\sf\orange{c}$ 12cm

______________________________

More to know:-

• A Parallelogram is a type of Quadrilateral it has two Parallel Sides. The opposite sides  of the Parallelogram are always equal.

• ${\fcolorbox{blue}{black}{\purple{\:\:\:\:\:\:Area of Parallelogram is Base × Height \:\:\:\:\:\:}}}$

• ${\fcolorbox{blue}{black}{\pink{\:\:\:\:\:\:Perimeter \ of \ Parallelogram \ is \ 2 × (a + b)\:\:\:\:\:\:}}}$

Diagram of the Parallelogram

$\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(1,1)(1,1)(6,1)\put(0.4,0.5){\bf D}\qbezier(1,1)(1,1)(1.6,4)\put(6.2,0.5){\bf C}\qbezier(1.6,4)(1.6,4)(6.6,4)\put(1,4){\bf A}\qbezier(6,1)(6,1)(6.6,4)\put(6.9,3.8){\bf B}\end{picture}$

[Note:- Kindly see the Diagram on the Web Browser] (Brainly.in)

____________________________________________