Question

If the area of a rectangle is 1260 cm2 and its perimeter 146 cm what is
O 28 cm
0 44 cm
53 cm
45 cm​

Answer 1

✬ Length & Breadth = 45 cm , 28 cm ✬

Step-by-step explanation:

Given:

• Area of rectangle is 1260 cm².
• Perimeter of rectangle is 146 cm.

To Find:

• What is its length of breadth ?

Solution: Let the length be l and breadth be b.

As we know that

★ Ar. of rectangle = Length × Breadth ★

★ Perimeter = 2(Length + Breadth) ★

A/q

• Perimeter = 146 cm

$\implies{\rm }$ 2(l + b) = 146

$\implies{\rm }$ l + b = 146/2

$\implies{\rm }$ l + b = 73

$\implies{\rm }$ l = 73 – b........i

Now,

• Area = 1260 cm²

$\implies{\rm }$ l × b = 1260

$\implies{\rm }$ (73 – b) × b = 1260

$\implies{\rm }$ 73b – b² = 1260

$\implies{\rm }$ 0 = b² – 73b + 1260

Using middle term splitting method

➯ b² – 73b + 1260

➯ b² – 45b – 28b + 1260

➯ b(b – 45) – 28(b – 45)

➯ (b – 28) (b – 45)

➯ b = 28 or b = 45

Taking the first value of b.

• Length = 73 – b = 73 – 28 = 45 cm
• Breadth = 28 cm

Answer 2

Answer:

Question

If the area of a rectangle is 1260 cm2 and its perimeter 146 cm what is

O 28 cm

0 44 cm

53 cm

45 cm

To find

Length of Breadth

Solution

Let's consider breadth to b

And length to l

$area \: of \: rectangle \: = l \times b \:$

$perimeter \: = 2 \times (l + b)$

$2(l + b) \: = 146cm \:$

$l \: + b \: = \frac{146}{2}$

$l \: + \: b \: = 73$

$l = 73 – b...i$

Then

Area = 1260 sq.cm

$l \: \: \times b \: = 1260$

$(73 – b) × b = 1260$

$73b – b² = 1260$

$0 = b² – 73b + 1260$

Middle term splitting method

b² – 73b + 1260

b² – 45b – 28b + 1260

b(b – 45) – 28(b – 45)

(b – 28) (b – 45)

b = 28 or b = 45

Take the Value of B

So, the Length = 73 – b = 73 – 28 = 45 cmBreadth = 28 cm

$\huge \fbox {HOPE IT HELP}$