Question

If the area of a rectangle is 35(a²bc + ab²c + abc²) and its length is 7abc, find its breadth.​

Answer 1

Step-by-step explanation:

5*7"abc(a+b+c)=area of rectangle

(7abc)(5(a+b+c))=length*breadth

breadth=5(a+b+c)

Answer 2

Answer :-

• Breadth of the rectangle = 5a + 5b + 5c.

Step by step explanation:

To find :-

• Breadth of the rectangle.

Solution:

Given that,

• Length = 7abc
• Area = 35(a²bc + ab²c + abc²)

We know,

Area of rectangle = length × breadth

Therefore :-

ᅠ

${\longrightarrow \bf 7abc \times breadth = 35({a}^{2}bc+{ab}^{2}c+{abc}^{2})}$

ᅠ

${\longrightarrow \bf { 35({a}^{2}bc+{ab}^{2}c+{abc}^{2}) } ÷ ( 7abc )}$

ᅠ

$\longrightarrow \bf ( 35a + 35b + 35c ) \div ( 7 )$

ᅠ

$\longrightarrow \bf 5a + 5b + 5c$

ᅠ

Hence, Breadth of the rectangle = 5a + 5b + 5c.