if the area of a rectangle is 5 times its width then determine its length
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hii mate!!
We know that the length of the rectangle is five times the width, so:
l = 5w
Where l is length and w is width. We also know that the perimeter is 84 cm, so:
2l + 2w = 84
Now we can plug in 5w for l since we found the equality earlier:
2(5w) + 2w = 84
and then solve for w:
10w + 2w = 84
12w = 84
w = 7
Now we know the width is 7 cm. Since the length is 5 times the width, the length is 35, and the area of the rectangle is 7 x 35 = 245 cm2.
hope it helps !!☺☺☺☺☺
We know that the length of the rectangle is five times the width, so:
l = 5w
Where l is length and w is width. We also know that the perimeter is 84 cm, so:
2l + 2w = 84
Now we can plug in 5w for l since we found the equality earlier:
2(5w) + 2w = 84
and then solve for w:
10w + 2w = 84
12w = 84
w = 7
Now we know the width is 7 cm. Since the length is 5 times the width, the length is 35, and the area of the rectangle is 7 x 35 = 245 cm2.
hope it helps !!☺☺☺☺☺
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