If the area of a rectangle is 63 cm^2 and its breadth is 7cm , find its (a) length, and (b) perimeter.
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Answers
Answered by
10
Hey Mate
your answer is here
let length = w cm
breadth = 7 cm
so,
Area = w×7
w = 63/7 = 9 cm
and,
perimeter = 2(w+7) = 2(9+7)= 2×16 = 32 cm
your answer is here
let length = w cm
breadth = 7 cm
so,
Area = w×7
w = 63/7 = 9 cm
and,
perimeter = 2(w+7) = 2(9+7)= 2×16 = 32 cm
Fathiha:
These Ans correct
Answered by
25
Hello,
Your answer ➡️
We have to find the length of given rectangle.
(a) Let the length of rectangle be x cm.
and
Given,
area = 63 cm ^2
breadth = 7 cm.
Now,
We know that,
Area of rectangle = length × breadth
63cm^2 = x × 7
63 / 7 = x
9 cm = x.
So,
Length = 9 cm.
Now,
(b) We have to find perimeter,
Perimeter = 2(l + b )
perimeter = 2(9 + 7 )
perimeter= 2 × 16
perimeter = 32 cm.
So,
(a) 9 cm.
(b)32 cm.
Hope it helps you.
☺️
Your answer ➡️
We have to find the length of given rectangle.
(a) Let the length of rectangle be x cm.
and
Given,
area = 63 cm ^2
breadth = 7 cm.
Now,
We know that,
Area of rectangle = length × breadth
63cm^2 = x × 7
63 / 7 = x
9 cm = x.
So,
Length = 9 cm.
Now,
(b) We have to find perimeter,
Perimeter = 2(l + b )
perimeter = 2(9 + 7 )
perimeter= 2 × 16
perimeter = 32 cm.
So,
(a) 9 cm.
(b)32 cm.
Hope it helps you.
☺️
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