Question

If the area of a rectangle is 84.com
and its lenoth is 12am then find the
perimeter of the rectangle​

Answer 1

Correction :

If the area of a rectangle is 84cm² and length is 12cm, then find the perimeter of the rectangle.

Here

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• Area of a rectangle = 84cm²
• Length of the rectangle = 12cm

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We've to find the value of breadth of the rectangle.

⠀ ______________________

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As we know that :

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$\underline{\boxed{\mathfrak\purple{\bigstar \: area \: of \: a \: rectangle \: = length \: \times breadth}}}$

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Now, we'll put the values of area and length of the rectangle in the area of the rectangle formula. By putting these two values, we can find the breadth of the rectangle.

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Putting the values :

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$\sf:\implies \: area \: of \: the \: rectangle = l \times b \\ \\ \\ \sf:\implies \: 84 = 12 \times b \\ \\ \\ \sf:\implies \: b = \frac{84}{12} \\ \\ \\ \sf:\implies \: b =\cancel \frac{84}{12} \\ \\ \\ \sf:\implies \: b = \underline{\boxed{\mathfrak\purple{7cm}}}\bigstar \\ \\ \\ \\ \sf\therefore{\underline{Hence, \: the \: breadth \: of \: the \: rectangle \: is \: \bold{7cm}}}$

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Now, we've the values of length and breadth both. So, we'll find the perimeter of the rectangle.

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As we know that :

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$\underline{\boxed{\mathfrak\purple{\bigstar \: perimeter \: of \: a \: rectangle \: = 2(length + breadth)}}}$

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$\sf:\implies \: perimeter \: of \: the \: rectangle \: = 2(l + b) \\ \\ \\ \sf:\implies \: perimeter \: of \: the \: rectangle \: = 2(12 + 7) \\ \\ \\ \sf:\implies \: perimeter \: of \: the \: rectangle \: = 2 \times 19 \\ \\ \\ \sf:\implies \: perimeter \: of \: the \: rectangle \: = \underline{\boxed{\mathfrak\purple{38 {cm}^{2} }}} \\ \\ \\ \\ \sf\therefore{\underline{Hence, \: the \: perimeter \: of \: the \: rectangle \: is \: \bold{38cm}.}}$

Answer 2

Answer:

Question-

If the area of a rectangle is 84cm sq.

and its lenoth is 12 cm then find the

perimeter of the rectangle.

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Given-

➵Area= ${84cm}{2}$

➵Length = 12 cm

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To Find-

➵Breadth.

➵Perimeter.

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Solution-

●Let's just find the breadth of the rectangle first.

Taking 'x' as the breadth.

$\color{black}\boxed{\colorbox{saffron}{Area - length×breadth}}$

${84}^{2} = {12}^{2} \times {x}^{2} \\ \\ = 84 = 12 \times x \\ \\ = \frac{84}{12} = x \\ \\ = 7 = x$

So, breadth = 7 cm

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●Now, let's find the perimeter of the rectangle.

$\color{black}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth) }}$

$= 2(12 + 7) \\ \\ = 2 \times 19 \\ \\ = 38cm$

Hence, perimeter = 38cm

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Required Answer-

$\rightarrow$ Breadth = 7 cm

$\rightarrow$ Perimeter = 38 cm