Question

If the area of a rectangle is 98 sq.cm. & it's length is double of it's breadth. Find it's
perimeter.​

Answer 1

Answer:

42cm

Step-by-step explanation:

according to question length =2* Breadth

area= length*breadth= 98

= 2*breadth*breadth=98

=(breadth)^2=98/2

=breadth=√49

breadth=7cm

length=2*breadth=2*7=14cm

perimeter=2(length+breadth)

=2*(14+7)

=2*21=42cm

Answer 2

Answer:

42 cm

Step-by-step explanation:

area of rectangle = 98 cm²

let the breadth of rectangle be = x

length of rectangle is double of breadth = 2x

area of rectangle = l × b = 98

$2x \times x = 98 \\ 2 {x}^{2} = 98 \\ {x}^{2} = \frac{98}{2} \\ {x}^{2} = 49 \\ x = \sqrt{49} \\ x = 7$

therefore the length of rectangle = 2 × 7 = 14 cm

breadth of rectangle = 7 cm

the perimeter of rectangle = 2(l + b)

= 2(14 + 7)

= 2 × 21

= 42 cm

the perimeter of rectangle is 42 cm

Hope you get your answer