If the area of a rectangle is x^2+x−12, what are its length and breadth?
Answers
Answer:
Length = ( x - 3 )
Breadth = ( x + 4 )
Given that ;
Area of the Rectangle = x² + x - 12
Area of the Rectangle = L × B
L × B = x² + x - 12
x² + x - 12
x² + 4x - 3x - 12
x ( x + 4 ) - 3 ( x + 4 )
( x - 3 ) ( x + 4 )
Hence ;
Length = ( x - 3 )
Breadth = ( x + 4 )
Proof :
Area of the Rectangle = L × B
( x - 3 ) ( x + 4 )
x² - 12 + 4x - 3x
Area = x² + x - 12
Solution : Here, we know through the question, area of rectangle is x² + x - 12.
Let, area of rectangle is f(x) = x² + x - 12 ----{1}
Now,
➜ f(x) = x² + x - 12
➜ f(x) = x² + 4x - 3x - 12
➜ f(x) = x (x + 4) - 3 (x + 4)
➜ f(x) = (x + 4) (x - 3)
Hence, length of rectangle is (x + 4) and breadth of rectangle is (x - 3)
Now, take value of x = 1
➜ Length of rectangle = (x + 4)
➜ Length of rectangle = (1 + 4)
➜ Length of rectangle = 5 unit
and
➜ Breadth of rectangle = (x - 3)
➜ Breadth of rectangle = (1 - 3)
➜ Breadth of rectangle = - 2 unit
Here, we know that, the width of a rectangle is neither negative nor zero. Hence value of x ≠ 1
Now, Now, take value of x = 2
➜ Length of rectangle = (x + 4)
➜ Length of rectangle = (2 + 4)
➜ Length of rectangle = 6 unit
and
➜ Breadth of rectangle = (x - 3)
➜ Breadth of rectangle = (2 - 3)
➜ Breadth of rectangle = - 1 unit
Here, we know that, the width of a rectangle is neither negative nor zero. Hence value of x ≠ 2
Now, Now, take value of x = 3
➜ Length of rectangle = (x + 4)
➜ Length of rectangle = (3 + 4)
➜ Length of rectangle = 7 unit
and
➜ Breadth of rectangle = (x - 3)
➜ Breadth of rectangle = (3 - 3)
➜ Breadth of rectangle = 0 unit
Here, we know that, the width of a rectangle is neither negative nor zero. Hence value of x ≠ 3
Now, Now, take value of x = 4
➜ Length of rectangle = (x + 4)
➜ Length of rectangle = (4 + 4)
➜ Length of rectangle = 8 unit
and
➜ Breadth of rectangle = (x - 3)
➜ Breadth of rectangle = (4 - 3)
➜ Breadth of rectangle = 1 unit
We know that, the width of a rectangle is neither negative nor zero. Hence, value of x is 4.
Therefore, we know that, value of x is always greater than 3. { ∴ value of x > 3 }
{ Hence, length of rectangle = 8 unit and breadth of rectangle = 1 unit }