Question

if the area of a rectangle is (x^2 - x -2) sq.unit then find its perimeter


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Answer 1

$area \: = {side}^{2}$

$= {side}^{2} = ( {x}^{2} - x - 2)$

$= side = \sqrt{( {x}^{2} - x - 2) }$

$= side = x - \sqrt{x - 2}$

Perimeter = 4xSide

$= 4x - 4 \sqrt{x - 2}$