Question

If the area of a rectangle is x2− 16, then find its possible dimensions.​

Answer 1

The possible dimensions of the rectangle are (x+4) and (x-4) as calculated using the properties of a rectangle.

To find the possible dimensions of a rectangle with an area of $x^2 - 16$, we need to factorize the expression$x^2 - 16$.

The given expression can be written as a difference of squares:

$x^2 - 16 = (x + 4)(x - 4)$

The area of a rectangle is given by the product of its length and width. In this case, the factors (x + 4) and (x - 4) represent the length and width of the rectangle, respectively.

Therefore, the possible dimensions of the rectangle are:

Length = x + 4

Width = x - 4

Alternatively, the dimensions can also be expressed as:

Length = x - 4

Width = x + 4

So, the possible dimensions of the rectangle are (x + 4) by (x - 4) or (x - 4) by (x + 4).

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