Question

if the area of a rectangle is x²+7x+12 and breadth is (x+3).then find its length and perimeters​

Answer 1

Answer:

Breadth=(x+3)

x= -3

Length=x²+7x+12

= (-3)²+7×-3+12

= 9-21+12

= -12+12

=0

So length is 0

Perimeter = 2(L+B)

=2(0+[-3])

=2×(0-3)

=2×-3

= -6