Question

If the area of a rectangle with length (4x) is (4x2+12x), find the width of the rectangle. Clearly show all of your work.

Answer 1

Step-by-step explanation:

Let the breadth be b cm

Now,

Length×Breadth= (4x2+12x)

4x × b = 8 +12x

b = (8+12x)/4x

b = 2/X + 3

Answer 2

Answer:

$\huge{\boxed{\rm{\red{width=(x+3)}}}}$

Step-by-step explanation:

Given:-

the area of a rectangle with length (4x) is (4x2+12x),

To find:-

find the width of the rectangle.

Solution:-

Length of the rectangle =4x units

Let the width be" b " units

Area of the rectangle =length×breadth

=>A=(4x)(b) sq.units

According to the problem,

Area of the rectangle =4x²+12x sq.units

=>(4x)(b)=4x²+12x

=>b=(4x²+12x)/(4x)

=>b=(4x)(x+3)/(4x)

Cancelling 4x , then

=>b=x+3 units

Answer:-

Width of the rectangle is (x+3) units

Used formula:-

Area of the rectangle =length×breadth