if the area of a rectangle with length (x-y) and breadth (2x-y) is the same kxy+2x^2-y^2 . find the k
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2x+y+8=4x-y.
or -2x+2y=-8.
or x-y = 4………………..(1).
x+4 = 2y.
x-2y = -4……………………(2).
Subtract eq (2) from (1) , y = 8 .
put y=8 in eq.(1) . x-8=4 => x=12 units
length (l) =2x+y+8=24+8+8=40 units.
bredth (b)=2×8= 16 units.
Perimeter = 2×(l+b)=2×(40+16) =112
Answer:
Area =l×b =40×16 =640 sq.units.
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