Question

If the area of a rectangular feild is given (5x²+x-6) and one of its side is (3x+2) , what is the other side​

Answer 1

Answer:

The length of other side of the rectangle is $\dfrac{(5x+6)(x-1)}{3x+2}$

Step-by-step explanation:

The area of rectangle with length $l$ and breadth $b$ is,

$Area = l \times b$

Given that,

$one side (length)= 3x+2\\\\Area = 5x^2+x-6$

Substitute these values in the formula for area.

$5x^2+x-6 =(3x+2) \times b\\\\\implies b =\dfrac{5x^2+x-6}{3x+2}\\\\b= \dfrac{(5x+6)(x-1)}{3x+2}$

Since there is no common factors, we cannot simplify it further.

Answer 2

CONCEPT :

• FIRST WE WILL WRITE FORMULA OF AREA
• LENGTH × BREADTH THEN, WE WILL multiply
• (3x+2) with breadth then, we will simplify
• 5x² + x - 6 with 3 x + 2 we get
• (5x + 6)(x - 1) /(3x + 2) so other side will be
• (5x + 6)(x - 1) /(3x + 2)

QUESTION :

• If the area of a rectangular feild is given (5x²+x-6) and one of its side is (3x+2) , what is the other side

GIVEN :

• area of a rectangular feild is given (5x²+x-6)

• one of its side is (3x+2)

TO FIND :

• what is the other side = ?

SOLUTION :

area rectangle formula = length × breadth

• one of its side = (3x+2)

area of a rectangular feild = (5x²+x-6)

then, we will putting the values :

rectangular field = (3x + 2) × breadth

breadth we have = 5x² + x - 6 / 3 x + 2

breadth we have = (5x + 6)(x - 1) /(3x + 2)

other side = (5x + 6)(x - 1) /(3x + 2)