Question

If the area of a rhombus 48m2 and one of its diagonal is 12 cm. Find its altitude​

Answer 1

Answer:

The other diagnel=d2=48x2/12 = 8

Side of Rhombus=v6^2+4^2 = 7.2

bxh=A

7.2xh=48

h = 48 /7.2=6.7cm

altitude=6.7cm

Answer 2

Answer:

33.58

Step-by-step explanation:

area of rhombus = 48 (given)

area of rhombus = 1÷2(d1× d2)

so 48 = 1÷2(12×d2)

96÷12= d2

d2 = 8

now all are are right tringles made by 2 triangles , also all sides of rhombus are equal

by Pythagoras theoram

(side of rhombus)^2 = 6^2 + 4^2

side of rhombus = √6^2+4^2

side of rhombus = √52 =7.2(approx)

height of rhombus = area ÷ side

=48÷7.2

=6.67m