if the area of a rhombus are 24cm square and one of a style men before cm find the perimeter of rhombus
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Step-by-step explanation:
The area of a regular rhombus is A=pq/2 , where p and q are the diagonals of the shape.
given A = 24 and p = 4
24=4q/2
48=4q
q=12
so the other diagonal is 12 cm long.
now, by Pythagorean theorem, each side of the rhombus (annotate as s) is given by:
s2=(p/2)2+(q/2)2
s2=(4/2)2+(12/2)2
s2=4+36
s2=40
s=210−−√
since there are 4 sides in a rhombus, so the perimeter of it is:
4∗210−−√
=810−−√
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