Question

If the area of a rhombus be 24 cm' and one of its diagonals be 4 cm. Find the perimeter of the
rhombus.
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Answer 1

Answer:

Area of rhombus = 1/2 * D1 * D2

24cm² = 1/2 * 4 * D2

D2 = 24*2/4 = 12 cm

now, we know that diagonals of rhombus cuts at 90° and bisect each other ,

therefore side of rhombus , (Let a)

a = √(6)²+(2)² = 2√10cm

perimeter of rhombus (since all sides are equal) = 4a = 4*(2√10) = 8√10 cm (Ans)

(Mark as brainlist)