Question

If the area of a rhombus is 48 cm² and one of its diagonals is 12 cm, find the side of the rhombus.
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Answer 1

area of rhombus= 1/2 × d1.d2

48÷12=1/2×d1

d1=4×2

=8 cm

We know that the diagonls of the rhombus bisect each other at 90' .

Let AB =BC= CD= AD be the sides of the rhombus.

So by Pythagoras theorem,

AB^2=(d1^2 ×d2^2 )1/4

AB SQ. = (64+144)×1/4

=208÷4

=52

AB= ROOT 52

=2_/13 cm

so the side of the rhombus is 2 root 13 cm.

I HOPE IT WILL WORK

MARK AS BRAINLEIST