if the area of a rhombus is 484cm² and length of one of its diagonal is 22 cm find the length of the other diagonal
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Let ABCD be the rhombus where AC = 10 cm and BD = 24 cm.
Let AC and BD intersect each other at O. Now, diagonals of rhombus bisect each other at right angles. Thus, we have.
Since AOB is a right angled triangle, by pythagoras theorem, we have.
Hence, AB = 13. Thus, length of each side of rhombus is 13 cm.
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Area of rhombus = d1 x d2 x 1/2
484 = 22 x d2 x 1/2
484 = 11 x d2
484/11 = d2
D2 or the other diagonal is 44 cm
484 = 22 x d2 x 1/2
484 = 11 x d2
484/11 = d2
D2 or the other diagonal is 44 cm
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