Question

If the area of a rhombus is 96 cm and one of its diagonals is 12
cm, find its perimeter.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Hi.....

Step-by-step explanation:

Area of rhombus =1/2 × d1 ×d2

1/2×d1×d2 =96

1/2×12×d2=96

d2=96/6

d2=16cm.......1

pls see the attachment

In right triangle ADO

AC=16 cm(from 1)

AO=8cm(Diagonals of rhombus bisect each other)

DO=6cm

AD^2=AO^2+OD^2

AD^2=8^2+6^2

AD^2=64+36

AD^2=100

AD=10cm

Perimeter =4 ×side

=4×10

=40cm