If the area of a rhombus is 96 cm and one of its diagonals is 12
cm, find its perimeter.
Answers
Answered by
3
Answer:
hello mate......
here is the answer
Step-by-step explanation:
pls mark it as the brainliest answer....
pls follow me....
have a bright future ahead....
thanks....
Attachments:
Answered by
10
Answer:
Hi.....
Step-by-step explanation:
Area of rhombus =1/2 × d1 ×d2
1/2×d1×d2 =96
1/2×12×d2=96
d2=96/6
d2=16cm.......1
pls see the attachment
In right triangle ADO
AC=16 cm(from 1)
AO=8cm(Diagonals of rhombus bisect each other)
DO=6cm
AD^2=AO^2+OD^2
AD^2=8^2+6^2
AD^2=64+36
AD^2=100
AD=10cm
Perimeter =4 ×side
=4×10
=40cm
Similar questions