Question

If the area of a rhombus is 96 cm sq and one of its diahonals is 16 cm,find its perimeter.

Answer 1

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Answer 2

area =product of diagonals /2
96= 16*y/2
y=12
dividing both diagonals by 2
x=8
y=6
by Pythagoras theorem
8^2 +6^2= side^2
64 +36=side^2
side=10
perimeter=4 *side
perimeter=40cm