Question

if the area of a rhombus is 96cm square and one of its diagonals is 12 cm long find the length of the other diagonal also find its perimeter​

Answer 1

Answer:

Newton's laws of motion relate an object's motion to the forces acting on it. In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration.

Answer 2

Answer:

THE LENGTH OF ANOTHER DIAGONAL IS 16 cm

AND THE PERIMETER OF THE RHOMBUS IS 40cm

Step-by-step explanation:

AREA OF THE RHOMBUS = 96 cm²

LENGTH OF ONE DIAGONAL = 12 cm

LET THE LENGTH OF ANOTHER DIAGONAL BE x

SO,

WE KNOW,

AREA OF RHOMBUS = 1/2*d₁*d₂

96 cm² = 1/2 * 12cm * x

96 cm² = 6 cm * x

 x = 96cm²/6cm

 x = 16cm

SO,

LENGTH OF ANOTHER DIAGONAL IS 16 cm

NOW,

WE CAN FIND THE LENGTH OF THE SIDE BY APPLYING PYTHAGORAS THEOREM,

SO,

LET THE LENGTH OF THE SIDE BE x

(P)²+(B)²=(H)²

(8cm)²+(6cm)²=(x)²

64cm²+36cm²=(x)²

100cm²=x²

x = √100cm²

x = 10cm

SO,

LENGTH OF THE SIDE IS 10cm

SO,

PERIMETER OF THE RHOMBUS = 4*SIDE

                                                      = 4*10cm

                                                      = 40cm

I HOPE YOU UNDERSTOOD THE QUESTION