Question

If the area of a right angled isosceles triangle is 32 sq. cm, then its perimeter is

Answer 1

Heyyyy mate..

Here is your answer..

given area of right angled isosceles triangle=32sq cm

1/2a^²=32

a^²=32×2=64

a= √64= 8 cm

now perimeter of triangle= (2+√2)×a

(2+√2)×8

16+8√2

hope it help you

Answer 2

Answer:

area=1/2 a^2

1/2a^2=32

a^2=32*2/1

a^2=64

a=root 64

a=8

perimeter=c+2a

=c+2*8

c+16

c you should find out

ans=27.312

Step-by-step explanation: