Question

If the area of a right isosceles triangle is 128sq m what will be the length of the indentical sides of the triangle

Answer 1

Step-by-step explanation:

Area of a triangle =

$\frac{1}{2} \times base \: \times height$

In an isosceles right angled triangle, the hypotenuse is the longest side and the base and height are equal.

Let, base = height = s

128 = 0.5 x s x s

128/0.5 = s x s

256 = s x s

s x s = 16 x 16

s = 16 m

So, the length of the identical sides is 16 m.

Answer 2

Step-by-step explanation:

let the isosceles side is x .

area of isosceles side =1/2×base ×height

1÷2×x×x=128sq m

x^2÷2=128 cross multiplication

x^2=256

x=16