Question

if the area of a right isosceles triangle is 50sq.m. what is the length of the identical sides of a triangle

Answer 1

We have,

in an right isosceles triangle, equal sides act as base and height . third side(unequal side) can't be base and height as it can never be equal to rest one.

Now,

let equal sides be 'a'.

we know,

area of a right isosceles triangle =

$\frac{1}{2} \times base \times height \\ = > \frac{1}{2} \times a \times a = 50 \\ = > \frac{1}{2} \times {a}^{2} = 50 \\ = > {a}^{2} = 100 \\ = > a = \sqrt{100} \\ = > a = 10m$
Regards

KSHITIJ

Answer 2

Heya Mate !!!

Your answer is 10m.

Step by Step Explanation :-

Let the equal sides be 'x'.

Now , Formula :-

Area of Right isosceles triangle = 1/2*base*height

So ,
$= > 1 \div 2 \times x \times x = 50$

$= > 1 \div 2 \times x{2} = 50$

$= > x {2} = 100$

$= > x \sqrt{100} = 10$

Hence , 10 m is the right answer.