if the area of a right isosceles triangle is50sq.m. what is the length of the identical sides of a triangle
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Answer:
We have,
in an right isosceles triangle, equal sides act as base and height . third side(unequal side) can't be base and height as it can never be equal to rest one.
Now,
let equal sides be 'a'.
we know,
area of a right isosceles triangle =
\begin{lgathered}\frac{1}{2} \times base \times height \\ = > \frac{1}{2} \times a \times a = 50 \\ = > \frac{1}{2} \times {a}^{2} = 50 \\ = > {a}^{2} = 100 \\ = > a = \sqrt{100} \\ = > a = 10m\end{lgathered}
2
1
×base×height
=>
2
1
×a×a=50
=>
2
1
×a
2
=50
=>a
2
=100
=>a=
100
=>a=10m
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