Question

If the area of a sectangular land is (a²-b²) sg. units
whose
breadth is (a-b) then, its length
is
​

Answer 1

i think it is rectangle

Let l , w be the length , width/breadth of the rectangle respectively.

then,

ar(rect) = l*w = a^2 - b^2 ---------(1)

now , w = (a-b) --------(2)

substituting the value of 2 in 1 , we get

_____answered by advik190____

L * ( a-b) = (a^2-b^2)

l = (a^2 - b^2) / (a-b) [using identity x^2 - y^2 = (x-y)(x+y)]

l = (a-b) (a+b) / (a-b)

l = a+b

Answer 2

❥A᭄ɴsᴡᴇʀ࿐

given,

• area=a²-b²

• breadth=(a-b)

• To find :- length of rectangle

• let length is l units

area of rectangle =length×breadth

a²-b²={a-b}×l ----------(1)

• using identity a²-b²=(a+b) (a-b)

• substituting value of a²-b² in equation (1)

• (a+b) (a-b)= (a-b)×l

• l=(a+b) unit

length of rectangle is (a+b) unit.