Question

If the area of a semi circular field is 30800 sq.M.Then the perimeter of the field is

Answer 1

Here is your answer > >

Area of semi circular field=30800 m^2

$\pi$r^2÷2=30800

22/7÷2 r^2=30800

r^2=19600

r^2=140^2

r=140 m

Perimeter of the field=2 $\pi$ r/2

=22/7×140

=440 m

Hope it helps!

Thankyou ☆ ☆

Answer 2

HERE IS YOUR ANSWER ...

$Let, \\ \\ Radius \: \: of \: \: the \: \: semi \: circular \: \: field \: = r \: \: metre$

$Given, \\ \\ Area \: \: of \: \: the \: \: semi \: \: circular \: field \: = 30800 \: \: sq.m \\ \\ = > \frac{\pi \: r {}^{2} }{2} = 30800 \\ \\ = > \pi \: r {}^{2} = 30800 \times 2 \\ \\ = > \frac{22}{7} \times r {}^{2} = 61600 \\ \\ = > r {}^{2} = 61600 \times \frac{7}{22} \\ \\ = > r {}^{2} = \frac{431200}{22} \\ \\ = > r {}^{2} = 19600 \\ \\ = > r = \sqrt{19600} \\ \\ = > r = 140$

$Radius \: \: of \: \: the \: \: semi \: circular \: \: field \: r = 140 \: \: m$

$So, \\ \\ Perimeter \: \: of \: \: the \: \: semi \: circular \: \: field \: \\ \\ = \frac{2\pi \: r}{2} \\ \\ = \pi \: r \\ \\ = ( \frac{22}{7} \times 140 \: ) \: \: m \\ \\ = 440 \: \: \: m$

$Hence \: perimeter \: \: of \: \: the \: \: semi \: circular \: \: \\ field \: = 440 \: \: metre$

________________________________

☆..HOPE IT HELPS YOU..☆