Question

if the area of a semicircular field is 15400 square metre then perimeter of a field is option A 160 route 2 metre option B 260 route2 metre option C 360 route2 option d 462 route2 metre​

Answer 1

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→Area of semicircular field = 15400 m²

$\frac{\pi {r}^{2} }{2} = 15400 \: {m}^{2} \\ \frac{11}{7} \times {r}^{2} = 15400 \: {m}^{2} \\ {r}^{2} = 15400 \times \frac{7}{11} \\ {r}^{2} = 1400 \times 7 \\ r = \sqrt{9800} \\ r = 98.99 \: m \\ r = 99 \: m \: \: \: \: \: \: \: (approx.)$

$Perimeter \: of \: circle = \pi \: r \\ = \frac{22}{7} \times 99 \\ = 359.985 \\ = 360 \: {m}^{2}$

Answer 2

Answer:

360root2

Step-by-step explanation:

Area of semicircle=15400

22/7 * r2 = 2(15400)

r2 = 9800

r = 70root2

Pm of semicircle = 22/7 + 2(70root2)

220root2 + 140root2

360root2