Question

If the area of a square field is 81sq.m, find the perimeter of the square.

Answer 1

$Let \: side \: of \: square \: field = a\: m$

$Area \: of \: the \: square \:field = 81 \: m^{2}$

$\blue { ( given ) }$

$\implies a^{2} = ( 9 \: m )^{2}$

$\implies a = 9 \: m \: --(1)$

$\red { Perimeter \: of \:the \: square } \\= 4a \\= 4 \times 9 \: m \\= 36 \: m$

Therefore.,

$\red { Perimeter \: of \:the \: square }\green {= 36 \: m}$

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Answer 2

Answer:

the correct answer is 36m