Question

If the area of a square increases by 44%, then the side of the square increases by what percent?

Answer 1

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GIVEN :

AREA OF SQUARE INCREASES BY 44%

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TO FIND :

THE PERCENTAGE BY WHICH SIDE IS INCREASED ....

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LET,

THE AREA OF THE SQUARE IS :

$100 \: {cm}^{2}$

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IT IS INCREASED BY 44%


AREA IS NOW ,


44% OF AREA + AREA

$\frac{44}{100} \times 100 \: {cm}^{2} \: + 100 \: {cm}^{2} \\ \\ 44 \: {cm}^{2} + 100 \: {cm}^{2} \\ \\ 144 \: {cm}^{2}$

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PREVIOUS SIDE :

$\sqrt{100 \: {cm}^{2} } \\ \\ 10 \: cm$

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NOW SIDE :

$\sqrt{144 \: {cm}^{2} } \\ \\ 12 \: cm$

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PERCENTAGE BY WHICH SIDE INCREASED :

$\frac{new \: side \: - \: previous \: side}{previous \: side \: } \: \times 100 \\ \\ \frac{12 - 10}{10} \times 100 \\ \\ 2 \times 10 \\ \\ 20\%$

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THUS IF AREA IS INCREASED BY 44% SIDE WILL INCREASE BY 20%

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