if the area of a square is 72ftsquare , find the length of its diagonals
Answers
Answered by
0
Answer:
Step-by-step explanation:
Given :
nth term , an= An + B………….(1)
On putting n = 1 in eq 1,
a1 = A + B
On putting n = 20 in eq 1,
a20 = A × 20 + B
a20 = 20A + B
a20 = l(last term) = 20A + B
By using the formula ,Sum of nth terms , Sn = n/2 [a + l]
S20 = 20/2 [a + l]
S20 = 10 [A + B + 20A + B]
S20 = 10 [21A + 2B]
S20 = 210A + 20B
Hence, the sum of first 20 terms of the given sequence is 210A + 20e
Step-by-step explanation:
Answered by
1
Answer:
12cm
Step-by-step explanation:
let side be =x
area of square = x^2=72
x=2√72
x=6√2
let length of the diognals =y
x2 + x2 = y2
y2 = (6√2)2 + (6√2)2
y2= 72 +72
y2= 144
y=√144
y = 12
Similar questions
Physics,
5 months ago
English,
5 months ago
English,
5 months ago
Math,
11 months ago
Chemistry,
11 months ago
Social Sciences,
1 year ago
Social Sciences,
1 year ago