If the area of a square of side 9cm is equal to the area of a rectangle of breadth 3cm, then find the perimeter of the rectangle.
Please give step-by-step explaination.
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Given :-
• Side of a square is 9cm.
• Breadth of a rectangle is 3 cm
• area of square = area of rectangle
To Find :-
• Perimeter of the rectangle.
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Area of a square = (side)²
=> (9)²
=> 81
Area of square = Area of rectangle = 81 cm²
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Let the Length of the rectangle be x
Then,
Area of a rectangle = Length × Breadth
=> 81 = 3 × x
=> 81 = 3x
=> x = 81/3
=> x = 27
Length of the triangle = 27 cm
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Perimeter of a rectangle = 2 ( length + breadth )
=> 2 ( 27 + 3 )
=> 2 ( 30 )
=> 60
Hence, the Perimeter of the rectangle is 60 cm
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