If the area of a square with side 'b'is
equal to the area of a triangle with base
'b', then the altitude of the triangle is
Answers
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0
Answer:
2b
Step-by-step explanation:
b2=1/2*b*a
:b=h/2
h=2b
Answered by
0
Area of square = ( side )^2
Are of triangle = 1/2 x base x height
But here given that side of square is ‘ b’ and base of triangle too is ‘b’.
So put are of square equal to area of triangle.
Let altitude be ‘a’.
1/2 x b x a= (b)^2
a= (b)^2 x 2/1x1/ b
a= b x 2
a= 2b
Hence , the length of the altitude is twice of that of base.
=> a= 2b
It may explain you the solution.
Are of triangle = 1/2 x base x height
But here given that side of square is ‘ b’ and base of triangle too is ‘b’.
So put are of square equal to area of triangle.
Let altitude be ‘a’.
1/2 x b x a= (b)^2
a= (b)^2 x 2/1x1/ b
a= b x 2
a= 2b
Hence , the length of the altitude is twice of that of base.
=> a= 2b
It may explain you the solution.
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