Question

*If the area of a trapezium is 25 sq.cm. and length of the parallel sides are 8 cm and 12 cm respectively ,what is the distance between the parallel sides?*

1️⃣ 2.5 cm
2️⃣ 5 cm
3️⃣ 1.25 cm
4️⃣ can't say​

Answer 1

Area of trapezium = 25 cm²
Parallel side 1 = 8 cm
Parallel side 2 = 12 cm

½ × (8+12) × h = 25
10 h = 25
h = 25/10
h = 2.5

Therefore, the distance between the parallel lines is 2.5 cm

Answer 2

Option(1) is correct.

Concept:

A trapezium is a convex quadrilateral with exactly one set of parallel opposite sides.

Given:

The area of the trapezium is $25sq.cm$.

The lengths of the trapezium are $8cm$ and $12cm$.

Find:

The distance between the trapezium's parallel sides.

Solution:

Area of the trapezium is $\frac{1}{2}*(L_1+L_2)*h$.

$25=\frac{1}{2}*(8+12)*h\\h=2.5cm$

Hence, the distance between the trapezium's parallel sides is $2.5cm$. Option(1) is correct.

Hence, the distance between the trapezium's parallel sides is $2.5cm$. Option(2) is incorrect.

Hence, the distance between the trapezium's parallel sides is $2.5cm$. Option(3) is incorrect.

Hence, the distance between the trapezium's parallel sides is $2.5cm$. Option(4) is incorrect.

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