Math, asked by survemahendra123, 7 hours ago

*If the area of a trapezium is 25 sq.cm. and length of the parallel sides are 8 cm and 12 cm respectively ,what is the distance between the parallel sides?*

1️⃣ 2.5 cm
2️⃣ 5 cm
3️⃣ 1.25 cm
4️⃣ can't say​

Answers

Answered by samruddhishinde432
0

Answer:

2.5 cm

Step-by-step explanation:

area of trapezium = sum of length of 2 parallel sides × distance between 2 parallel sides /2

25 = 8+12 × distance Between 2 parallel sides

25 = 20 × x

x = 25 ÷ 20

x = 1.25 cm

divided by 2 will be multiply by 2

answer = 2.5 cm

Answered by arya004patel
1

Answer:

(1)

Step-by-step explanation:

Area of trapezium = {(a+b)h}/2

      =>  25 = \frac{(8 + 12)(h)}{2}

       => 25 = 10h

         => h = 2.5 cm

(1) 2.5 cm

Mark it as brainliest dear

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