If the area of a Trapezium is 28 cm^2, and two parallel sides are 8cm and 60dm respectively, find the altitude.
Answers
Answered by
0
Answer:
altitude = 14/17
Step-by-step explanation:
l = ?
a = 8 cm
b = 60 cm
area = 28cm^2
According To Question
area of trepazium = 1/2×l(a+b)
28=1/2×l(8+60)
28×2÷1=l×68
56÷68=l
14÷17=l
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Answered by
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Given : area of a Trapezium is 28 cm², and two parallel sides are 8cm and 60dm respectively,
To find : the altitude
Solution:
dm = decimeters
1 m = 10 dm
1 dm = 10 cm
=> 60dm = 60 * 10 = 600 cm
area of a Trapezium = (1/2)( sum of parallel side) * altitude
=> (1/2)(8 + 600)* h = 28
=> (1/2)( 608)* h = 28
=> 304h = 28
=> h = 28/304
=> h = 0.0921 cm
altitude = 0.0921 cm
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