if the area of a trapezium is 28m^2 and two parallel sides are 8m and 60 dm. find the height
Answers
Answered by
1
Answer:
height of a trapezium is 4m.
Step-by-step explanation:
convert into dm to m
10dm = 1m
1dm =1/10
60dm= 0.1*60
= 6m
therefore,
area of trapezium=1/2(sum of parallel side)*height
28m^2 = 1/2(8+6)*h
28m^2 = 1/2*14*h
h = 28*2/14
h = 4m
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Answered by
2
Step-by-step explanation:
area of the trapezium=1/2×h(8+6)
1/2h(8+6)=28
1/2h×14=28
h=28×2/14
h=4
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