If the area of a Trapezium is 96 sq.cms And the length of its parallel sides are 9 cm and 7 cm ,then the distance between the parallel sides is
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Hi here is your answer,
Area = 96 cm
lengths = 7 cm , 9 cm
height =
=1/2h(b1+b2)
= 1/2×h (7+9)
1/2×16=h
h =8 cm
so, the height of the trapezium is 8 cm.
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Area = 96 cm
lengths = 7 cm , 9 cm
height =
=1/2h(b1+b2)
= 1/2×h (7+9)
1/2×16=h
h =8 cm
so, the height of the trapezium is 8 cm.
plz mark as brainlest and thanks me
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