Question

If the area of a triangle is 1176 and base:corresponding altitude is 3:4,then find the perimeter of triangle

Answer 1

let the base and altitude be 3y and 4y respectively
a=1/2 x b x h
1176= 1/2 *3y*4y
1176= 1/2 *12y2
1176*2=12y2
2352÷12=y2
$\sqrt{638 \div 3}$