Question

if the area of a triangle is 6 CM square and two of its sides are 5cm and 3cm find the third side

Answer 1

Your answer ➡️ 4 cm


Becoz that this triangle is right angle triangle


Apply Pythagoras theorem


5²-3²= x²

x²= 25-9=16


X= 4...... Ans(1)


Area of triangle = 1/2×base×height


6 = 1/2 × 3 × X


X= 6×2/3=4 cm.....Ans(2)


We can say on Ans(1) & Ans(2) that ans 4 is right



Hope it helps you

Answer 2

Answer:

Step-by-step explanation:

Given sides are 3cm, 4cm and 5cm.

We know that semi-perimeter of a triangle s = a + b + c/2

= 3 + 4 + 5/2

= 12/2

= 6cm.

Using Heron's formula, we know that Area of the triangle:

= \sqrt{s(s-a)(s-b)(s-c)}=

s(s−a)(s−b)(s−c)

​

= \sqrt{6(6 - 3)(6 - 4)(6 - 5)}=

6(6−3)(6−4)(6−5)

​

= \sqrt{6(3)(2)(1)}=

6(3)(2)(1)

​

= \sqrt{36}=

36

​

6 cm^2.6cm

2

.

Therefore the area of triangle = 6cm^2.

Hope this helps!