Question

If the area of ​​a triangle is 96 square meters and the land is twenty meters, what is the height of the triangle?​

Answer 1

Answer:

20

Step-by-step explanation:

r 1 = (s−a)Δ ,r 2 = (s−b)Δr 3= (s−c)Δ(using basics formulas)s−a= 896 ,s−b= 12

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)2c=40from the eq ((1)+(2))

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)2c=40from the eq ((1)+(2))c=20,

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)2c=40from the eq ((1)+(2))c=20,2b=32from the eq ((1)+(3))

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)2c=40from the eq ((1)+(2))c=20,2b=32from the eq ((1)+(3))b=16

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)2c=40from the eq ((1)+(2))c=20,2b=32from the eq ((1)+(3))b=162b=24from the eq ((2)+(3))

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)2c=40from the eq ((1)+(2))c=20,2b=32from the eq ((1)+(3))b=162b=24from the eq ((2)+(3))a=12

96 ,s−b= 1296,s−c= 2496( 2b+c−a )=12,( 2a+c−b)=8,( 2a+b−c)=4b+c−a=24−(1),a+c−b=16−(2),a+b−c=8−(3)2c=40from the eq ((1)+(2))c=20,2b=32from the eq ((1)+(3))b=162b=24from the eq ((2)+(3))a=12∴c=20 (greatest side)

Answer 2

Answer:

the answer is here

answer is 8