If the area of a triangle is given and its ratio of perimeter is given how to find perimeter
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Suppose the area given is A square units, and the ratio of sides are a:b:c
The length of the original sides will be ax,bx,cx where x is a scalar multiple.
Semi perimeter, s=ax+bx+cx2=(a+b+c)x2
Now, apply Herron’s formula….
AA216A2x=s(s−ax)(s−bx)(s−cx)−−−−−−−−−−−−−−−−−−−−√=s(s−ax)(s−bx)(s−cx)=(a+b+c)x2⋅(a+b−c)x2⋅(b+c−a)x2⋅(c+a−b)x2=(a+b+c)(a+b−c)(b+c−a)(c+a−b)x4=2A−−√(a+b+c)(a+b−c)(b+c−a)(c+a−b)−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√4
Perform the calculation
P=(a+b+c)x
and using the value found for x completes the solution.
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