if the area of a triangle whose base is 20 cm equal to the area of a circle radius is 7 cm find the height of the triangle
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area of triangle = bh/2
area of circle =
ATQ
22x7 x 7 / 7 = 20 x h /2
11 x 7 = 5h
77/5 = h
h = 15.4 cm
area of circle =
ATQ
22x7 x 7 / 7 = 20 x h /2
11 x 7 = 5h
77/5 = h
h = 15.4 cm
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