Question

If the area of a triangle whose base is 22 cm is equal to the area of a circle of radius 7 cm , then the height od the triangle is

Answer 1

Answer :-

h = 14 cm

Given :-

Base of traingle = 22 cm

radius of circle = 7 cm

To find :-

The height of the triangle.

Solution:-

Let the height of the triangle be h m.

Area of traingle is given by :-

→$A = \dfrac{1}{2}\times b \times h$

put the value of b.

→$A = \dfrac{1}{2}\times 22 \times h$

→$A = 11h$

Now,

Area of circles is given by :-

→$A = \pi r^2$

→$A = \dfrac{22}{7} \times (7)^2$

→$A = \dfrac{22}{7}\times 49$

→$A = 154 cm^2$

A/Q

The area of triangle is = Area of circle.

→$154 = 11h$

→$h = \dfrac{154}{11}$

→$h = 14 cm$

hence,

The height of triangle is 14 cm.

Answer 2

Hi there !

Given that :-

Base of a triangle = 22cm

Radius of circle = 7cm

Area of circle --> πr²

Here, area of circle= $\frac{22}{7} \times 7 \times 7$

=154 cm²

Area of triangle = area of circle [Given in question]

=$\frac{1}{2} \times b \times h \:$

$= \frac{1}{2 } \times 22 \times h = 154$

$=11 \times h = 154 \\ \\ h = \frac{154}{11} \\ \\ = 14$

Thus, height of the triangle is 14cm.

Thankyou :)