Question

If the area of an equalateral
triangle is 81√3 cm² ​

Answer 1

It is not given what is to be found, however

area of equilateral ∆ = 81√3 sq cm

√3/4 (side)^2 = 81√3

side^2 = 81√3*4/√3

side^2 = 81*4

side = √81*4

= 9*2

side = 18 cm

perimeter of triangle = 3*(side)

= 3*18

= 54

again,

area of ∆ = 81√3

(1/2) x base x height = 81√3

(1/2) x 18 x height = 81√3

9 x height = 81√3

height = 81√3/9

height = 9√3

The question must be to find one of the above three I guess.