If the area of an equilateral triangle is 18√3cmsqure .find its height
Answers
Answered by
4
Area of an equilateral triangle = √3/4 a²
Where a² = square of the side
Also area would be 1/2 × a × h
Where h = height
So,
√3/4 a² = 18√3
=> a² = 18√3 ÷ √3/4
=> a² = 18√3 × 4/√3
=> a² = 18 × 4
=> a = √18 × √4
=> a = √9 × √2 × √4
=> a = 3 × 2√2
=> a = 6√2
Now area = 1/2 × a × h
=> 1/2 × a × h = 18√3
=> 1/2 × 6√2 × h = 18√3
=> 3√2 × h = 18√3
=> h = 18√3 × 1/3√2
=> h = 6√3/√2
=> h = 6√3/√2 ×√2/√2
=> h = 6√6/2
=> h = 3√6
Answer :- 3√6 cm
Where a² = square of the side
Also area would be 1/2 × a × h
Where h = height
So,
√3/4 a² = 18√3
=> a² = 18√3 ÷ √3/4
=> a² = 18√3 × 4/√3
=> a² = 18 × 4
=> a = √18 × √4
=> a = √9 × √2 × √4
=> a = 3 × 2√2
=> a = 6√2
Now area = 1/2 × a × h
=> 1/2 × a × h = 18√3
=> 1/2 × 6√2 × h = 18√3
=> 3√2 × h = 18√3
=> h = 18√3 × 1/3√2
=> h = 6√3/√2
=> h = 6√3/√2 ×√2/√2
=> h = 6√6/2
=> h = 3√6
Answer :- 3√6 cm
gegfhfhbduwobshakdbs:
side of the ∆ is 12√2cm not 6√2cm. check it : )
Answered by
3
given area of the equilateral ∆ = 18√3cm²
formula for the area of an equilateral ∆ is √3/4s²
where 's' is the side of the equilateral ∆.
therefore √3/4 × s² = 18√3cm²
=> √3s² = 18√3 × 4
=> √3s² = 72√3cm²
=> s² = 72√3/√3
=> s² = 72cm²
=> s = √(2 × 2 × 2 × 3 × 3)
=> s = 12√2cm
hence the side of the equilateral triangle is 12√2cm
we all know the basic and the easiest formula for finding the area of a triangle. that is 1/2 × b × h
now we got the side 12√2cm. put 12√2 as base.
=> 1/2 × 12√2 × h = 18√3cm²
=> 6√2 × h = 18√3cm²
=> h = 18√3/6√2
=> h = 3√3/√2
by rationalizing we get,
=> h = 3√3/√2 × √2/√2
=> h = 3√6/2cm
hence the height of the ∆ is 3√6/2cm.
Similar questions
Environmental Sciences,
7 months ago
Political Science,
7 months ago
Math,
1 year ago
Math,
1 year ago
Chemistry,
1 year ago
Biology,
1 year ago