if the area of an equilateral triangle is 81√3 cm^2 find its perimeter
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let side is a
then
√3a²/4=81√3
or a²=81*4
or a=9*2
or a=18
then perimeter is =3a=3*18=54..........(ans)
then
√3a²/4=81√3
or a²=81*4
or a=9*2
or a=18
then perimeter is =3a=3*18=54..........(ans)
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