if the area of an equilateral triangle is 81√3 .find its perimeter
Answers
Answered by
9
1) area of an equilateral triangle= 81root3
(root3)/4*a^2= 91 root3
Here a is side
a^2= (81*root3*4)/(root3)
a^2= 81*4
a^2=(324)
a^2=(18)^2
a =18
2) perimeter = 3a
=3*18
=54 units
Answered by
1
We know that
Area of equilateral triangle = √3/4 (side)2
Substituting the values
81 √3 = √3/4 (side)2
By further calculation
Side2 = (81 √3 × 4)/ √3
So we get
(side)2 = 81 × 4
side = √(81 × 4)
side = 9 × 2 = 18 cm
So the perimeter of equilateral triangle = 3 × side
= 3 × 18
= 54 cm
Similar questions